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Python math.hypot() Method
Python math.hypot() Method
Python math.hypot() method in python is used to returns the Euclidean norm, sqrt(x*x, y*y). Euclidean norm – is the length of the vector from the origin to point (x,y) , where x and y are perpendicular and base.
Syntax:math.hypot(x1, x2, x3, ..., xn)
Parameter Values
| Parameter | Description |
|---|---|
| x1, x2, x3, ..., xn | It is required to represent coordinates between the two numbers and more |
import math
parendicular = 2
base = 15
print (math.hypot(parendicular, base))
Output:
15.132745950421556
Example 2:
15.132745950421556
import math
x = 6
y = 2
print(math.hypot(x,y))
x = 6.8
y = 4.14
print(math.hypot(x,y))
x = 5
y = 1
print(math.hypot(x,y))
x = 6
y = -1
print(math.hypot(x,y))
x = -9
y = 2
print(math.hypot(x,y))
x = -4
y = -6
print(math.hypot(x,y))
Output:
6.324555320336759
7.961130572977685
5.0990195135927845
6.082762530298219
9.219544457292887
7.211102550927978
6.324555320336759
7.961130572977685
5.0990195135927845
6.082762530298219
9.219544457292887
7.211102550927978
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